Question

If `8/3 L` of a gas at room temperature exerts a pressure of `35 kPa` on its container, what pressure will the gas exert if the container's volume changes to `7/4 L`?

Answer 1

`P_2=53,bar(3)" "kPa`

Explanation:

`P_1*V_1=P_2*V_2" Boyle's law"`
`35*8/3=P_2*7/4`

`P_2=(35*8*4)/(7*3)`

`P_2=53,bar(3)" "kPa`