# If 8/3 L of a gas at room temperature exerts a pressure of 35 kPa on its container, what pressure will the gas exert if the container's volume changes to 7/4 L?

##### 1 Answer
Mar 29, 2016

${P}_{2} = 53 , \overline{3} \text{ } k P a$

#### Explanation:

${P}_{1} \cdot {V}_{1} = {P}_{2} \cdot {V}_{2} \text{ Boyle's law}$
$35 \cdot \frac{8}{3} = {P}_{2} \cdot \frac{7}{4}$

${P}_{2} = \frac{35 \cdot 8 \cdot 4}{7 \cdot 3}$

${P}_{2} = 53 , \overline{3} \text{ } k P a$