Question

If 8 grams of methane CH4 react and only 6 grams of water is collected what is your percentage yielded?

Answer 1

`33.33%`

Explanation:

The reaction is

`"CH"_4 + 2"O"_2 = "CO"_2+ 2"H"_2"O"`

Thus for every mole of `"CH"_4`, the reaction yields two moles of water.

Now, the molecular weight of `"CH"_4` is 16, and that of water is 18.

Since the amount of methane combusting is 0.5 moles, we should get a mole of water, i.e. 18 gms of water under ideal conditions(complete combustion)

The percentage yield is

`(6 " gm")/(18" gm") times 100 %= 33.33%`