# If 8 L of a gas at room temperature exerts a pressure of 15 kPa on its container, what pressure will the gas exert if the container's volume changes to 15 L?

May 26, 2017

The pressure is $= 8 k P a$

#### Explanation:

We apply Boyle's Law

${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$

The initial volume is ${V}_{1} = 8 L$

The initial pressure is ${P}_{1} = 15 k P a$

The final volume is ${V}_{2} = 15 L$

The final pressure

${P}_{2} = {V}_{1} / {V}_{2} \cdot {P}_{1}$

$= \frac{8}{15} \cdot 15$

$= 8 k P a$