# If 8 L of a gas at room temperature exerts a pressure of 32 kPa on its container, what pressure will the gas exert if it the container's volume changes to 4 L?

Dec 28, 2017

$32 k P a$

#### Explanation:

As, here the temperature is constant
Hence,according to the ideal gass law:

${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$

$\mathmr{and} , 8 L \times 32 k P a = 4 L \times {P}_{2}$

$\mathmr{and} , {P}_{2} = \frac{8 L \times 32 k P a}{4 L}$

:.P_2=64kPacolor(brown)

So,we have to exert (64-32) kPa or 32 kPa pressure.