Question

If `8 L` of a gas at room temperature exerts a pressure of `32 kPa` on its container, what pressure will the gas exert if it the container's volume changes to `4 L`?

Answer 1

`32kPa`

Explanation:

As, here the temperature is constant
Hence,according to the ideal gass law:

`P_1V_1=P_2V_2`

`or,8Lxx32kPa=4LxxP_2`

`or,P_2=(8Lxx32kPa)/(4L)`

`:.P_2=64kPacolor(brown)`

So,we have to exert (64-32) kPa or 32 kPa pressure.