# If 8 L of a gas at room temperature exerts a pressure of 32 kPa on its container, what pressure will the gas exert if the container's volume changes to 4 L?

${P}_{2} = 64 \text{ } k P a$
$\text{use the Boyle's law}$
${P}_{1} \cdot {V}_{1} = {P}_{2} \cdot {V}_{2}$
$32 \cdot \cancel{8} = {P}_{2} \cdot \cancel{4}$
${P}_{2} = 2 \cdot 32$
${P}_{2} = 64 \text{ } k P a$