# If 8 L of a gas at room temperature exerts a pressure of 32 kPa on its container, what pressure will the gas exert if the container's volume changes to 5 L?

Dec 24, 2016

The pressure is $= 51.2 k P a$

#### Explanation:

We apply Boyle's Law

${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$

${P}_{1} = 32 k P a$

${V}_{1} = 8 L$

${V}_{2} = 5 L$

${P}_{2} = \frac{{P}_{1} {V}_{1}}{V} _ 2 = \frac{32 \cdot 8}{5} = 51.2 k P a$