Question

If `9/7 L` of a gas at room temperature exerts a pressure of `8 kPa` on its container, what pressure will the gas exert if the container's volume changes to `5/4 L`?

Answer 1

`288/35 kPa` or `8.23 kPa`

Explanation:

We can obtain the final pressure via Boyle's Law

The numbers 1 and 2 represent the initial and final conditions, respectively.

Let's identify the known and unknown variables:

`color(violet)("Knowns:")`
- Initial Volume
- Final Volume
- Initial Pressure

`color(gold)("Unknowns:")`
- Final Pressure

All we have to do is rearrange the equation to solve for the final pressure. We do this by dividing both sides by `V_2` in order to get `P_2` by itself like this:
`P_2=(P_1xxV_1)/V_2`

Now all we do is plug in the values and we're done!

`P_2= (8kPa xx 9/7cancel"L")/(5/4\cancel"L")` = `288/35kPa`