# If 9/7 L of a gas at room temperature exerts a pressure of 8 kPa on its container, what pressure will the gas exert if the container's volume changes to 5/4 L?

Dec 21, 2016

$\frac{288}{35} k P a$ or $8.23 k P a$

#### Explanation:

We can obtain the final pressure via Boyle's Law

The numbers 1 and 2 represent the initial and final conditions, respectively.

Let's identify the known and unknown variables:

$\textcolor{v i o \le t}{\text{Knowns:}}$
- Initial Volume
- Final Volume
- Initial Pressure

$\textcolor{g o l d}{\text{Unknowns:}}$
- Final Pressure

All we have to do is rearrange the equation to solve for the final pressure. We do this by dividing both sides by ${V}_{2}$ in order to get ${P}_{2}$ by itself like this:
${P}_{2} = \frac{{P}_{1} \times {V}_{1}}{V} _ 2$

Now all we do is plug in the values and we're done!

${P}_{2} = \left(8 k P a \times \frac{9}{7} \cancel{\text{L")/(5/4\cancel"L}}\right)$ = $\frac{288}{35} k P a$