If 9/7 L97L of a gas at room temperature exerts a pressure of 8 kPa8kPa on its container, what pressure will the gas exert if the container's volume changes to 5/4 L54L?

1 Answer
Dec 21, 2016

288/35 kPa28835kPa or 8.23 kPa8.23kPa

Explanation:

We can obtain the final pressure via Boyle's Law thescienceclassroom.orgthescienceclassroom.org

The numbers 1 and 2 represent the initial and final conditions, respectively.

Let's identify the known and unknown variables:

color(violet)("Knowns:")Knowns:
- Initial Volume
- Final Volume
- Initial Pressure

color(gold)("Unknowns:")Unknowns:
- Final Pressure

All we have to do is rearrange the equation to solve for the final pressure. We do this by dividing both sides by V_2V2 in order to get P_2P2 by itself like this:
P_2=(P_1xxV_1)/V_2P2=P1×V1V2

Now all we do is plug in the values and we're done!

P_2= (8kPa xx 9/7cancel"L")/(5/4\cancel"L") = 288/35kPa