# If 98.5 mol of an ideal gas is at 1.73 atm and 477 K, what is the volume of the gas?

May 27, 2016

$V = 2230 L$

#### Explanation:

Use the ideal gas law: $P V = n R T$.

The volume then could be obtained after rearranging the aforementioned expression as:

$V = \frac{n R T}{P}$

Therefore, $\implies V = \frac{98.5 \cancel{m o l} \times 0.0821 \frac{L \cdot \cancel{a t m}}{\cancel{K} \cdot \cancel{m o l}} \times 477 \cancel{K}}{1.73 \cancel{a t m}} = 2229.7 L \cong 2230 L$ (rounded to 3 significant figures)