If 98.5 mol of an ideal gas is at 1.73 atm and 477 K, what is the volume of the gas?

1 Answer
May 27, 2016

Answer:

#V=2230L#

Explanation:

Use the ideal gas law: #PV=nRT#.

The volume then could be obtained after rearranging the aforementioned expression as:

#V=(nRT)/P#

Therefore, #=>V=(98.5cancel(mol)xx0.0821(L*cancel(atm))/(cancel(K)*cancel(mol))xx477cancel(K))/(1.73cancel(atm))=2229.7L~=2230L# (rounded to 3 significant figures)