# If a 0.075 liter solution contains .0877 moles of CuCO_4, what is the molarity?

Well, let's make the solute $C u C {l}_{2}$...........Why? Because there ain't no such beast as $C u C {O}_{4}$. (There are copper carbonyls, but I don't think that's what you mean.)
$\text{Molarity}$ $=$ $\text{Moles of solute"/"Volume of solution}$
$= \frac{0.0877 \cdot m o l}{0.075 \cdot L} = 1.17 \cdot m o l \cdot {L}^{-} 1$..............