Question

If a 2.50 l balloon at 0 oC were heated to 85.0 oC, what would its new volume be?

Answer 1

`"3.28 L"`

Explanation:

From Charle’s Law

`"V"_1/"T"_1 = "V"_2/"T"_2`

`"V"_2 = "T"_2 × "V"_1/"T"_1`

`"V"_2 = (85.0 + 273) cancel"K" × "2.50 L"/((0 + 273) cancel"K") = "3.28 L"`