# If a 2 kg object is constantly accelerated from 0m/s to 16 m/s over 6 s, how much power musy be applied at t=1 ?

$\frac{16}{3}$Newtons
$F = m \cdot a$ where $m$ is the mass, $F$ the power and $a$ the acceleration.
As the acceleration is constant $\implies a = \frac{{v}_{f} - {v}_{0}}{t} = 16 \frac{m}{s} / 6 s = \frac{8}{3} \frac{m}{s} ^ 2$
Then, the power applied is $F = 2 k g \cdot \frac{8}{3} \frac{m}{s} ^ 2 = \frac{16}{3} N$.