Question

If a 4.37-kg object experiences a 6.47-N force for a duration of 8.47-second, then what is the momentum change of the object?

Answer 1

We know that when an impulsive force (`F`) acts on a particle of mass `m` moving with velocity `v`,for time `t`,which had a velocity of `u` before the force had acted upon it,then,

`F =(m(v-u))/t`

Or, change in momentum=`m(v-u) =Ft=6.47×8.47 =54.80 Kg.ms^-1`