If a = 5 & c = 6, then?

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Answer 1 · 2018-05-02T08:05:46

#/_A=56.4^circ#

#/_B=33.6^circ#

Since we have a right angled triangle, we can use #sin# and #cos.

#sintheta=O /H#
#/_A=theta=sin^-1(O /H)=sin^-1(5/6)~~56.4^circ#

#costheta=A/H#
#/_B=theta=cos^-1(A/H)=cos^-1(5/6)~~33.6^circ#

Answer 2 · 2018-05-02T08:21:52

#angle A =approx 56.44^o#, #angle B approx 33.56^o#

Here we have a right #triangle ABC#

Side #a=5# and side #c=6#

#:. sin A = a/c = 5/6#

#angle A = arcsin (5/6)#

#approx 56.44^o#

Since the sum of the angles of any triangle is #180^o#

#angle B approx 180 - 90 - 56.44#

#approx 33.56^o#