If a 60 kg person on a 15 kg sled is pushed with a force of 300 N, what will be a person's acceleration?
1 Answer
Explanation:
Recall that Newton's
#color(blue)(|bar(ul(color(white)(a/a)F_"net"=macolor(white)(a/a)|)))# where:
#F_"net"=# sum of all forces acting on the object
#m=# mass
#a=# acceleration
For this problem, we will set the positive directions to be east and down.
Start by breaking the variable,
#F_"net"=ma#
#F_"net"=(m_"person"+m_"sled")a#
Assuming there is no friction involved, the only acting force in the
#a=F_"app"/(m_"person"+m_"sled")#
Substitute your known values.
#a=(300N)/(60kg+15kg)#
#a=color(green)(|bar(ul(color(white)(a/a)4m/s^2color(white)(a/a)|)))#