If a current of 8 A passing through a circuit generates 72 W of power, what is the resistance of the circuit?

Mar 14, 2018

$1.125 \Omega$

Explanation:

$P = {I}^{2} R$

power = current^2 * resistance

this can be rearranged to give

$R = \frac{P}{{I}^{2}}$

resistance = power / (current^2)

here, current $= 8 A$

${8}^{2}$ = $64$

power $= 72 W$

$\frac{P}{{I}^{2}} = \frac{72}{64}$

$R = \frac{72}{64} \Omega$

$= \frac{9}{8} \Omega$

$= 1.125 \Omega$