If a force of 50 N stretches a spring 0.10 m, what is the spring constant?

1 Answer
Mar 26, 2018

The spring constant is #500 \ "N/m"#.

Explanation:

We use Hooke's Law, which states that,

#F=kx#

  • #F# is the force in newtons

  • #k# is the spring constant

  • #x# is the extension of the spring in meters

Solving for #k#, we get,

#k=F/x#

Now, we plug in the values, and we get,

#k=(50 \ "N")/(0.1 \ "m")#

#=500 \ "N/m"#