If a projectile is shot at a velocity of 2 m/s and an angle of pi/3, how far will the projectile travel before landing?

$\frac{\sqrt{3}}{4.9} \text{m}$
Range ($R$) of a projectile is given by the formula
$R = \frac{{u}^{2} \sin \left(2 \theta\right)}{g}$
R = (("2 m/s")^2 × sin((2pi)/3))/("9.8 m/s"^2) = ("4 m"^2//"s"^2 × sqrt(3)/2)/("9.8 m/s"^2) = sqrt(3)/4.9 "m"