# If a projectile is shot at a velocity of #2 m/s# and an angle of #pi/4#, how far will the projectile travel before landing?

##### 1 Answer

it will land about 0.638 m far.

#### Explanation:

We have to write down the equations of motion:

where

We have:

#h_0=0# and#x_0=0# ;#v=2 \ ms^(-1)# #theta= pi/4 # #a=-g \ ~~ -9.81 \ ms^(-2). #

We have

When the projectile lands, it reaches the ground so we have y=0 at that moment.

The equations of motion at the landing are:

from the first equation

The other becomes:

Performing the calculation we eventually have: