If a projectile is shot at a velocity of 21 m/s and an angle of pi/4, how far will the projectile travel before landing?

Mar 9, 2017

$\text{the answer "x_m"=44.95 " meters}$

Explanation:

$\text{we can calculate using the fallowing formula }$

${x}_{m} = \frac{{v}_{i}^{2} \cdot \sin \left(2 \alpha\right)}{g}$

$\text{Where :}$

${x}_{m} : \text{maximum distance}$
${v}_{i} = \text{initial velocity "v_i=21 " } \frac{m}{s}$

$\alpha = \frac{\pi}{4} \text{ , "2*alpha=2*pi/4=pi/2" , } \sin \left(\frac{\pi}{2}\right) = 1$

$g : \text{gravitational acceleration " g=9.81" } \frac{N}{k g}$

${x}_{m} = \frac{{21}^{2} \cdot 1}{9.81}$

${x}_{m} = \frac{441}{9.81}$

${x}_{m} = 44.95 \text{ meters}$