# If a projectile is shot at a velocity of 28 m/s and an angle of pi/12, how far will the projectile travel before landing?

$39.2 m$
Range of projectile is given as ${u}^{2} \sin \frac{2 \theta}{g}$ (derivation done using the equation $R = u \cos \theta \cdot T$ and $T = 2 u \sin \frac{\theta}{g}$ , where, $R$ stands for range, $T$ for total time of flight, $\theta$ is angle of projection and $u$ is the velocity of projection)
Given, $u = 28 \frac{m}{s}$ and $\theta = \frac{\pi}{12}$
So, $R = 39.2 m$