If a radio and bulb ra h of resistance 3ohm are connected in series of 12volts battery the potential difference across each will be, a, 6v b, 3v c, 13v?

1 Answer
Jul 27, 2018

The answer is #option (a)#

Explanation:

The resistance of the radio is #r_1=3 Omega#

The resistance of the bulb is #r_2=3 Omega#

The total resistance in the circuit is

#r=r_1+r_2=3+3=6 Omega#

Aplly Ohm's Law

#U=rI#

The voltage of the battery is

#U=12V#

Therefore,

The current in the circuit is

#I=U/r=12/6=2A#

The potential diffirence across the radio or the bulb is

#u=3*2=6V#

The answer is #option (a)#