If #alpha# and #beta# are the zeroes of the quadratic polynomial #x^2 +5x+6# find a quadratic polynomial whose zeroes are #1/ alpha# and #1/ beta?#

1 Answer
Feb 19, 2018

#6x^2+5x+1#

Explanation:

Given:

#ax^2+bx+c" "# with #a != 0# and #c != 0#

Then:

#1/x^2(ax^2+bx+c) = c(1/x)^2+b(1/x)+a#

So the zeros of #ax^2+bx+c# are the reciprocals of the zeros of #cx^2+bx+a#

Hence a quadratic whose zeros are the reciprocals of the zeros of:

#x^2+5x+6#

is:

#6x^2+5x+1#