If #alpha# and #beta# are the zeroes of the quadratic polynomial #x^2 +5x+6# find a quadratic polynomial whose zeroes are #1/ alpha# and #1/ beta?#
1 Answer
Feb 19, 2018
Explanation:
Given:
#ax^2+bx+c" "# with#a != 0# and#c != 0#
Then:
#1/x^2(ax^2+bx+c) = c(1/x)^2+b(1/x)+a#
So the zeros of
Hence a quadratic whose zeros are the reciprocals of the zeros of:
#x^2+5x+6#
is:
#6x^2+5x+1#