Question

If an object is moving at `0 m/s` and accelerates to `60 m/s` over `34/5` seconds, what was the object's rate of acceleration?

Answer 1

`veca~~9m/s^2["forward"]`

Explanation:

The acceleration of an object is given by the formula:

`color(blue)(|bar(ul(color(white)(a/a)color(black)(veca=(Deltavecv)/(Deltat))color(white)(a/a)|)))`

`ul("where:")`
`veca=`acceleration, in metres per second squared `(m/s^2)`
`Deltavecv=`change in velocity, in metres per second `(m/s)`
`Deltat=`change in time, in seconds `(s)`

Since you are given the change in velocity as well as the change in time, you can go straight to solving for the object's acceleration.

In this case, we will let the forward direction be positive.

`a=(Deltav)/(Deltat)`

`color(white)(xxx)=(v_f-v_i)/(Deltat)`

Substituting in the values,

`color(white)(xxx)=(60m/s-0m/s)/(34/5s)`

`color(white)(xxx)=8.82m/s^2`

`color(white)(xxx)~~color(green)(|bar(ul(color(white)(a/a)color(black)(9m/s^2)color(white)(a/a)|)))`