If an object is moving at #10 m/s# over a surface with a kinetic friction coefficient of #u_k=3 /g#, how far will the object continue to move?

1 Answer
May 10, 2016

Answer:

#S=16.67" " m#

Explanation:

#"Friction Force: " F_f=U_k*m*g#

#F_f=3/cancel(g)*m*cancel(g)#

#F_f=3*m#

#"deceleration of object : " a=F_f/m" The Newton's second law"#

#a=(3*cancel(m))/cancel(m)#

#a=3 m/s^3#

#v_f^2=v_i^2-2*a*S#

#v_f=0#
#v_i=10m/s#
#a=3m/s^2#
#S=?#

#0=10^2-2*3*S#

#100=6*S#

#S=100/6=50/3#

#S=16.67" " m#