If an object is moving at #22 m/s# over a surface with a kinetic friction coefficient of #u_k=11 /g#, how far will the object continue to move?

1 Answer
Jun 3, 2016

Answer:

#Delta x=22" "m" (area under graph)"#

Explanation:

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#u_k=11/g#
#v_i=22" "m/s#

#"Friction force: "F_f=u_k*m*g#

#F_f=11/g*m*g" ; "F_f=11m#

#F_f=m*a" ; "11*m=m*a" ; "a=11 " "m/s^2#

#v_f^2=v_i^2-2*a*Delta x#

#0=v_i^2-2*a*Delta x#

#v_i^2=2*a*Delta x#

#Delta x=v_i^2/(2*a)#

#Delta x=22^2/(2*11)#

#Delta x=22" "m" (area under graph)"#