# If an object is moving at 4 m/s and accelerates to 6 m/s over 3 seconds, what was the object's rate of acceleration?

Apr 12, 2016

$a = \frac{2}{3} \frac{m}{s} ^ 2$

#### Explanation:

${v}_{i} = 4 \frac{m}{s} \text{ initial velocity of object}$

${v}_{l} = 6 \frac{m}{s} \text{ last velocity of object}$

$t = 3 s$

a=?" acceleration of object"

$\text{the object's rate of acceleration is given as } a = \frac{\Delta v}{\Delta t}$

$\Delta v = {v}_{l} - {v}_{i} = 6 - 4 = 2 \frac{m}{s}$

$\Delta t = 3 - 0 = 3$

$a = \frac{2}{3} \frac{m}{s} ^ 2$