If an object is moving at #4 m/s# over a surface with a kinetic friction coefficient of #u_k=12 /g#, how far will the object continue to move?

1 Answer
Dec 13, 2015

Answer:

Its a simple application of kinematics.

Explanation:

Normal force in this scenario is #N= mg#
Frictional force #f=\mu mg=u_kmg#
#u_k=\frac{12}{g}#, therefore #f=12m#, where the #g#s get cancelled.
Acceleration #a=12m/s^2#
Therefore using the kinematic formula
#v^2-u^2=2as#, where #s# is the distance traveled, #u#, #v# are the initial and final velocities and #a# acceleration.
#u=4 m/s#
#v=0#
#a=12m/s^2#
Therefore, #s=u^2/{2a}#
substituting values given we get #s={4\times4}/{2\times12}=16/24=2/3=0.667m#