Question

If an object with a mass of `10 kg` is moving on a surface at `3m/s` and slows to a halt after `4 s`, what is the friction coefficient of the surface?

Answer 1

`u_k~=0,076`

Explanation:

`v_l=v_i-a t`
`0=3-4 a" "a=3/4 m/s^2`
`F_f=m a`
`u_k cancel(m) g=cancel(m) a`
`u_k *9,81=3/4`
`u_k~=0,076`