If atmospheric pressure on a certain day is 749 mmHg, what is the partial pressure of nitrogen, given that nitrogen is about 78% of the atmosphere?

Dec 12, 2016

In a gaseous mixture, the partial pressure exerted by a component gas is the same as the pressure it would exert if it alone occupied the container.

Explanation:

The total pressure is the SUM of the individual partial pressures.

Now P_"atmospheric"=P_(N_2)+P_(O_2)+P_("other gases")

We measured, ${P}_{\text{atmospheric}} = 749 \cdot m m \cdot H g$,

P_"dinitrogen"=749*mm*Hgxx78%~=580-600*mm*Hg