If cos B = 0.5, <B =?

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i dont understand the question at all

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Answer 1 · 2018-04-27T10:21:35

#angle B=60^circ or angle B=pi/3#

I think your question is:

"If #cosB=0.5,then, angle B= ?#"

We know that,

#cosB=0.5=5/10=1/2#

From the Trig.Table,

#angle B=60^circ or angle B=pi/3#

Note:

In general,

#color(red)(costheta=cosalpha=>theta=2kpi+-alpha,kinZZ#

#cosB=cos(pi/3)=>B=2kpi+-pi/3,kinZZ#