# If f(x) = 2x^2+1 and g(x) = 3x-2, what is the value of f(g(-2))?

$f \left(g \left(- 2\right)\right) = 129$
First we need $g \left(- 2\right)$:
$g \left(- 2\right) = 3 \left(- 2\right) - 2 = - 6 - 2 = - 8$
Now we put that value into $f \left(x\right)$:
$f \left(g \left(- 2\right)\right) = f \left(- 8\right) = 2 {\left(- 8\right)}^{2} + 1 = 2 \left(64\right) + 1 = 129$