Question

If `f(x) =-e^(2x-1)` and `g(x) = 5sin^2x^2`, what is `f'(g(x))`?

Answer 1

`f'(g(x))=-2e^(10sin^2x^2-1)`

Explanation:

`f(x)=-e^(2x-1)` and `g(x)=5sin^2x^2`

Therefore, `f'(x)=-e^(2x-1)xxd/dx(2x-1)=-2e^(2x-1)`

Hence, `f'(g(x))=-2e^(2xx5sin^2x^2-1)`

or `f'(g(x))=-2e^(10sin^2x^2-1)`