Question

If f(x) is a function that is odd and even simultaneously then f(3)-f (2) is equal to ?

Answer 1

0

Explanation:

`f(x)` is even `implies f(-x) = f(x)`

`f(x)` is odd `implies f(-x) = -f(x)`

So

`f(x) = f(-x) = -f(x) implies`

`\color(red)(f(x) = 0)`

Thus `f(3)-f(2) = 0`