# If #f(x)= (x^2-9)/(x+3)# is continuous at #x= -3#, then what is #f(-3)#?

##### 1 Answer

May 27, 2015

Apparently your function is not continuous at

But, if you write:

now you have:

so that now you have:

Your

so that basically

Graphically:

graph{(x^2-9)/(x+3) [-10, 10, -5, 5]}