Question

If `f(x)= x^2-x` and `g(x) = 3x^( 2/3 )`, what is `f'(g(x))`?

Answer 1

`f'(g(x))=6x^(2/3)-1`

Explanation:

`f'(x)=2x-1`
`f'(g(x))=2(g(x))-1`
`f'(g(x))=2(3x^(2/3))-1`
`f'(g(x))=6x^(2/3)-1`