If #f(x) = x/3-2# and #g(x)=(4x-1)/(x-2)#, what is #g[f(15)]#?
1 Answer
Jun 26, 2018
Explanation:
#"begin by evaluating "f(15)#
#f(color(red)(15))=color(red)(15)/3-2=5-2=3#
#"now evaluate "g(3)#
#g(color(magenta)(3))=(4xxcolor(magenta)(3)-1)/(color(magenta)(3)-2)=(12-1)/1=11#
