If f(x)=x^3+3x^2+4x+5 and g(x)=5x then what is d/dx g(f(-1))?

1 Answer
Jan 9, 2018

See below.

Explanation:

I'm not absolutely sure what you are asking here. #g(f(-1))# would be a constant, and therefore its derivative would be #0#. I will do the problem as I think it should be.

If #f(x)=x^3+3x^2+4x+5# and #g(x)=5x#

Then:

#g(f(x))=5(x^3+3x^2+4x+5)=5x^3+15x^2+20x+25#

#dy/dxg(f(x))=dy/dx(5x^3+15x^2+20x+25)=15x^2+30x+20#

Plugging in #x=-1#

#15(-1)^2+30(-1)+20=color(blue)(5)#