Question

If `g(x) = 5x ^ { 3} + 2x ^ { 2} + 3x - 4`, what is `g(0)`?

Answer 1

See a solution process below:

Explanation:

To evaluate `g(0)` we need to substitute `color(red)(0)` for each `color(red)(x)` in `g(x)`

`g(color(red)(x)) = 5color(red)(x)^3 + 2color(red)(x)^2 + 3color(red)(x) - 4` becomes:

`g(color(red)(0)) = (5 * color(red)(0)^3) + (2 * color(red)(0)^2) + (3 * color(red)(0)) - 4`

`g(color(red)(0)) = (5 * color(red)(0)) + (2 * color(red)(0)) + (3 * color(red)(0)) - 4`

`g(color(red)(0)) = color(red)(0) + color(red)(0) + color(red)(0) - 4`

`g(color(red)(0)) = -4`