If I combine 15.0 grams of calcium hydroxide with 75.0 mL of 0.500M HCl, how many grams of calcium chloride would be formed?

1 Answer
May 30, 2018

Answer:

Approx...#2*g#...

Explanation:

We follow the stoichiometric equation....

#Ca(OH)_2(s) + 2HCl(aq) rarr CaCl_2(aq) + 2H_2O#

#n_(Ca(OH)_2)=(15.0*g)/(74.09*g*mol^-1)=0.203*mol#

And we got with respect to #HCl# a molar quantity of...

#75.0*mLxx0.500*mol*L^-1xx10^-3*L*mL^-1=0.0375*mol#

Clearly the calcium hydroxide is present in molar excess....and at most we can form #(0.0375*mol)/2# of calcium chloride...a mass of #110.98*g*mol^-1xx(0.0375*mol)/2=??*g#..

The question operates under a faulty premise...because the species in solution after addition of the acid would be #Ca(OH)Cl#