# If I have 2.00 moles of solute dissolved into 1.00 L of solvent. What's the molality?

To answer this question we will assume that the solvent is water. The mass of the solvent will be 1.00kg.

NOTE: The density of water is 1g = 1mL

$\frac{1.00 L}{1}$x$\frac{1000 m L}{1 L}$x$\frac{1 g}{1 m L}$x$\frac{1 k g}{1000 g}$= 1.00 kg

To calculate the molality we use the relationship-

$\frac{m o l s o l u t e}{k g s o l v e n t}$ = molality

$\frac{2.00 m o l s o l u t e}{1.00 k g s o l v e n t}$ = 2.00$m$