# If i have 4.00 moles of gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature?

Mar 13, 2018

$67.3 \text{K}$

#### Explanation:

Use the equation
$P V = n R T$

$P = 5.6 \text{atm"= 5.6 xx 10^5 "Pa}$
$V = 12 {\text{L"=12/1000"m}}^{3}$
$n = 4 \text{mol}$
$R = 8.31 \text{J/mol}$ ( this is always constant)
$T$ is unknown

By rearranging the equation....

$T = \frac{P V}{n R}$
Thus,
$T = 67.3 \text{K}$