# If I wanted to find the interior angle sum of a polygon with 102 sides, what would it be?

Feb 1, 2016

${18000}^{\circ}$

#### Explanation:

we know,
the sum of the interior angels of a polygon is,

$s = {180}^{\circ} \left(n - 2\right)$

for the polygon with 102 sides,

$s = {180}^{\circ} \left(102 - 2\right)$

$= {180}^{\circ} \times 100$

$= {18000}^{\circ}$

Apr 13, 2016

${18000}^{\circ}$

#### Explanation:

Remember the formula

color(brown)(a=(n-2)180^circ

Where

color(blue)(a="sum of interior angles"

color(blue)(n="number of sides of the polygon"

Now, we need to find $a$

$\rightarrow a = \left(102 - 2\right) {180}^{\circ}$

$\rightarrow a = \left(100\right) {180}^{\circ}$

color(green)(rArra=18000^circ