If integral from 1 to 5 of f(x)dx=20, find integral from 5 to 1 of (f(x)-2)dx?
1 Answer
Feb 12, 2018
# int_5^1 f(x)-2 \ dx = -12 #
Explanation:
We are given that:
# I_1 = int_1^5 \ f(x) \ dx = 20 #
Then we seek:
# I = int_5^1 f(x)-2 \ dx #
# \ \ = - \ int_1^5 f(x)-2 \ dx #
# \ \ = int_1^5 \ 2- f(x) \ dx #
# \ \ = int_1^5 \ 2 \ dx - int_1^5 \ f(x) \ dx #
# \ \ = [2x]_1^5 - I_1 #
# \ \ = 2(5-1) - 20 #
# \ \ = -12 #