# If little earths could be strung about the equator of the sun like a string of pearls, how many pearls would there be in the necklace?

Jun 27, 2016

345

#### Explanation:

I like this nice imagination. This is a reason for my instant answering

of the question.

Sun's equatorial radius is 696342 km. So, the length of the equator

is $2 \pi X 686342$ km.

The diameter of the Earth is 12756 km.

So, for studding the equator-neck of the Sun with Earth as pearls,

the number of pearls (Earths) required will be

$\frac{2 \pi X 696342 + 6378}{12756}$

$= 345.66$ or 345 (lower rounding)

If it is real pearl, my answer is 514.7348027 billions

My imagination goes beyond.

Earth is shedding pearls continuously, over a year, from behind, How

many were there in the so formed orbit necklace?

Rare Tahiti pearls are 20 mm wide. Normal range of size of pearls is

6 mm-11 mm. So, I take the average 8.5 mm for the size of the pearl

as building block for the virtual orbit-lacing of the Earth's (very nearly

a circular) orbit. 1 AU = 149597871 km is the radius of this orbit.

Answer for my question = $2 \pi \frac{149597871 k m}{8.5 m m}$

$$       =((2pi)(149597871 ))/((8.5)(10^(- 6)))

=110582,4877 billions, nearly.


I further imagine that Mother Earth creates a spiral orbit-lace, without smashing the pearls in orbit, from the starter lace..