If #log_3 5 = x#, what is #x#?
1 Answer
Mar 6, 2016
Explanation:
We can use the change of base formula:
#log_a b = (log_c b) / (log_c a)#
with
Using common (base
#log_3 5 = (log_10 5) / (log_10 3) ~~ 0.69897 / 0.47712 ~~ 1.465#