Question

If sec^2(θ) = 5/3 find the values of cos^2(θ) tan^2(θ) + sin^2 (θ) tan^2 (θ) ?

Answer 1

`cos^2thetatan^2theta+sin^2thetatan^2theta=2/3`

Explanation:

`cos^2thetatan^2theta+sin^2thetatan^2theta`

= `(cos^2theta+sin^2theta)tan^2theta`

= `tan^2theta`

= `sec^2theta-1`

= `5/3-1`

= `2/3`