Question

If sec(t) = 3, how do you find the exact value of `sin^2 (t)`?

Answer 1

Find `sin^2 t`

Ans: `sin^2 t = 8/9`

Explanation:

`sec t = 1/(cos t) = 3` --> `cos t = 1/3` --> `cos^2 t = 1/9`
`sin^2 t = 1 - cos^2 t = 1 - 1/9 = 9/9 - 1/9 = 8/9`