If #sinh x = 3/2#, how do you find exact values for cosh x and tanh x? Trigonometry Right Triangles Relating Trigonometric Functions 1 Answer Ratnaker Mehta Aug 25, 2016 #cosh x=sqrt13/2#. #tanh x=3/sqrt13#. Explanation: WE know that, #cosh^2x-sinh^2x=1#. Hence, #cosh^2x=sinh^2x+1=(3/2)^2+1=13/4# #:. cosh x=sqrt13/2#. #tanh x=sinh x/cosh x=3/sqrt13#. Answer link Related questions What does it mean to find the sign of a trigonometric function and how do you find it? What are the reciprocal identities of trigonometric functions? What are the quotient identities for a trigonometric functions? What are the cofunction identities and reflection properties for trigonometric functions? What is the pythagorean identity? If #sec theta = 4#, how do you use the reciprocal identity to find #cos theta#? How do you find the domain and range of sine, cosine, and tangent? What quadrant does #cot 325^@# lie in and what is the sign? How do you use use quotient identities to explain why the tangent and cotangent function have... How do you show that #1+tan^2 theta = sec ^2 theta#? See all questions in Relating Trigonometric Functions Impact of this question 15609 views around the world You can reuse this answer Creative Commons License