If the force (at 90∘ to the lever arm) applied is 15 N and it is applied at 2.0 m from the pivot point (point of rotation), what is the torque on the lever?

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Rachel Share
Jan 26, 2018

$t = 30$ $N$ $m$

Explanation:

The equation for tourqe is $t = f \times d$, where tourqe is $t$, $f$ is force in Newtons, and $d$ stands for distance in meters

So, $t = 15 \times 2$

$t = 30$ $N$ $m$

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