If the largest angle of an isosceles triangle measures 106 degrees, what is the measure of the smallest angle?

Mar 8, 2018

${37}^{\circ}$

Explanation:

$\text{An isosceles triangle has 2 equal base angles and an }$
$\text{angle at it's vertex}$

$\text{the largest angle is the vertex } = {106}^{\circ}$

$\Rightarrow \text{base angles } = {\left(180 - 106\right)}^{\circ} / 2 = {37}^{\circ}$

$\text{the smallest angle in the triangle } = {37}^{\circ}$